So I am using an OPA1612 op amp and I need positive and negative supplies for my application. I intend to use a 9 volt battery.
This is the circuit I plan to use to get a +4.5V and a -4.5V. You can see that my negative probe is connected to the node between the capacitors C3 and C4, and that the voltage at the top and bottom is 4.5 and -4.5 volts respectively. To me it seems that that middle node IS MY GROUND because it is the 0 voltage point. Evidently, the positive terminal of the battery is now at +4.5V and the negative terminal of the battery is at -4.5 volts so my battery no longer has the 0 voltage point right?
NOW HERE IS WHERE THE PROBLEM IS!!!
This is the entire circuit. As you can see I have 3 other ground connections to the 10mH inductor, the potentiometer, and the stereo jack. For the PCB design itself (which I am doing in Altium Designer if that matters), how do I create these ground connections when I am using a single battery???
When I was researching this project I found a device that is identical to what I wanted to make by someone who sells it as a product. Here is his schematic and board. What in the heck are those H1,H2,H3, and H4 connections and why are they connected to the ground plane????
It seems to me that those H1,H2,H3, and H4 connections are the big holes with the screws in them in that second picture. So does that mean that the screws themselves are the ground???? I am just confused how this guy created a "ground" in his PCB when he split his battery to 4.5 and -4.5 volts.
In my PCB if I connect the midpoint of the voltage divider to the ground points (10mH inductor, the potentiometer, and the stereo jack) with traces and then connect all of those to a ground copper plane with a via, will that be my ground even if the capacitors C3/C4 and resistors R4/R5 aren't perfectly matched??