4
\$\begingroup\$

How to calculate the voltage V0 across the 8ohm resistor? Using mesh analysis I get an answer(120V) which is different from the correct answer.

Left loop, $$4I_1+V_1=120$$ Right loop, $$10I_2+2I_3+V_2=0$$ Outer loop, $$-120+4I_1+8I_3-8I_2=0$$

Solving I get, $$I_3=15A \text{ and }V_0=120V$$

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Is any data given about the transformer? Pleas edit the question to show the steps that you have followed. \$\endgroup\$ – AJN Nov 28 '20 at 7:48
  • \$\begingroup\$ Also, please use MathJax to format equations nicely. Make clear your effort up to point stuck and ask help to get unstuck, not expecting free homework service. \$\endgroup\$ – relayman357 Nov 28 '20 at 11:09
  • \$\begingroup\$ Which 8 ohm resistor? \$\endgroup\$ – Hot Licks Nov 28 '20 at 15:52
  • \$\begingroup\$ @HotLicks The one which is connected to both primary and secondary side. And \$V_0\$ is the voltage across the resistor. \$\endgroup\$ – Rakshith Krish Nov 29 '20 at 12:01
4
\$\begingroup\$

I suspect the transformer is ideal, and it is where you may be stuck. Current into a polarity dot on one side means current out of the dot on other side. Their magnitude will be exactly per turns ratio.

So, draw an arrow going into left side dot and assign it a current variable. Then draw an arrow coming out of the other dot (or in to non-polarity dot side if easier) and assign it the same current variable, but scale it by \$1/2\$. Also, assign a voltage variable to one side, scale it and assign with appropriate polarity on the other side as well. Then you can write KVL and KCL equations to solve.

enter image description here

Below I have assigned variables that should help you write the needed equations,

enter image description here

\$\endgroup\$
10
  • \$\begingroup\$ I'm able to find the current flowing in the secondary winding. But I'm confused about the voltage across the 8ohm resistor because it is connected to both primary and the secondary winding. Should I consider another current I3 and solve for it? \$\endgroup\$ – Rakshith Krish Nov 28 '20 at 11:40
  • \$\begingroup\$ Yes, and it will fit nicely into the two node equations. Also add voltage variable across your transformer to help you write KVL equations. I added a picture to clarify. \$\endgroup\$ – relayman357 Nov 28 '20 at 12:10
  • \$\begingroup\$ How should I take the equation for 8ohm resistor connected to both primary and secondary circuit? Should V1 and V2 be included in the equation? \$\endgroup\$ – Rakshith Krish Nov 28 '20 at 12:37
  • \$\begingroup\$ I would write KVL equations for left loop, right loop, and then an overall loop around perimeter of entire circuit. That, with the two node equations should suffice. You can edit your question to show us your equations. \$\endgroup\$ – relayman357 Nov 28 '20 at 12:45
  • 1
    \$\begingroup\$ See if my edit (added circuit with suggested variables) helps. The current up through the bottom right 8Ω resistor (from KCL) is \$\frac{i_2}{2}+i_3\$. \$\endgroup\$ – relayman357 Nov 28 '20 at 14:24

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.