I have a doubt, if anyone here can help me...
How can I find the minimum value of 'io' that can be achieved by only modifying 'R'?
Thanks in advance
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Voltage at non-inverting input is 3.75V and therefore voltage at inverting input is also 3.75V.
Current through top 30k resistor is 3.75/30k = 125uA and this will be the current through R irrespective of its value.
With R = 0 Ohms, current through 10k load is 3.75/10k = 375uA
Therefore with R = 0 Ohms, Io = 375uA + 125uA = 500uA which is the minimum value of Io.
Any increase in R above 0 Ohms increases the voltage across 10k load and therefore increases Io above its minimum value of 500uA.