I have been working through Boylestad and I am having trouble with this folling question.
h = 50.
this one i'm finding difficult because the current source depends on another part of this network. I tried applying Kirchhoff's law around the both loops to get loop currents \$I_1\$ and \$I_2\$. $$hI = I_1 - I_2$$
So \$I = I_1\$
Then I got $$hI_1 = I_1 - I_2$$
$$0 = I_1(1-h) - I_2$$
And I used kirchhoff's around the outer loop to get the second equations. $$20 = I_1(2000) + I_2(2000)$$
So I used these two equations using determinants but I didn't get the result in the book which was \$19.62\angle 53^\circ\$
Am I on the right path here or is there a better way to try and get the correct answer?
Now correctly completed with the help of @TimWescott and @relayman357 with the correct equations: $$I_1(1+h)-I_2=0$$ $$I_1(2000) + I_2(2000) = 20\angle 53^\circ$$
Then using determinant to determine \$I_2\$ to then find \$VR2\$.