Hello everyone, I am a freshman in computer science, and as we are dealing with a lot of hardware, we stumbled upon transistors. We learned that if a transistor is in cutoff mode, it basically acts as a switch that is not closed.
In the picture I provided, we can see that the transistor is in cutoff mode, as the voltage supplied to the base is not enough (it should be around 0.6V). But, if I had an open switch, the voltage between the collector of the NPN transistor and the ground should be 5 Volts. In this case, however, it says 4.881V. I have no idea where the voltage is lost along the way, because as the current does not pass through the transistor, no current should flow through the entire branch, and therefore there should be no loss of source voltage. What am I getting wrong?