An LDO will have to decrease the voltage by \$5V - 3.3V = 1.7V\$, and you have specified the current at \$1A\$. This means the power dissipated by the regulator is \$ 1.7V \cdot 1A = 1.7W \$. You will need a heatsink, and you will be wasting quite a lot of energy. You will have to decide if this is a problem for your application, or not.
The switching regulator will be more efficient, won't require a heatsink, but is more complex. It would probably more efficient to derive your 3.3V from 24V if you go with a switching regulator. There are also some switching designs that can output multiple voltages through multiple taps on the secondary of the transformer which may simplify your design. And yes, the switching regulator will result in more electromagnetic noise than the LDO. Again, that's a design decision you will have to make based on your application.