Disclaimer: I’m computer scientist.

I want to measure a faint varying magnetic field with a coil. The frequency domain I’m interested in is ultra low (< 10kHz). The source of the varying magnetic field is a liquid contained in an Eppendorf. An Eppendorf is 40mm long and has a diameter of 10 mm. The voltage at the terminals of the coil is reported to be in the µV range, but I assume it depends on the coil.

Lab grade high gain low noise voltage amplifiers are out of my budget. I was considering using a cheap card based on the AD620 chip that is claimed to be able to provide a gain of x10,000 (e.g. https://fr.aliexpress.com/item/32889722488.html). It’s the only solution that I found so far. But these devices are advertised for a minimum voltage resolution of 50µV at best if I understood correctly.

I would like to know if I can compensate this limitation by using a coil with a stronger amplification factor (e.g. 10,000 turns, 0.2mm wire, 11mm internal diameter, 30mm height), by hoping that this would increase the amplitude of the voltage at the terminals of the coil.

Another naive question is if I could also increase the signal amplitude if I put 2 to 5 coils in series around the Eppendorf, each one with a ferrite core.

Edit 1: I now have the coil and the ad620, but the LM358 amplifier is still in transit.

Here are the coil specifications:

  • turns: 2000
  • wire diameter: 0.1mm
  • height: 25mm
  • internal diameter: 12mm
  • external diameter: 13.91mm
  • inductance (L): 20.5563mH
  • DC resistance: 180.942 Ω

At 1kHz, the impedance is 310.1 Ω.

enter image description here

For the ad620, the bad news is that the documentation is all in Chinese. I’m translating it with deepl.com. We’ll see how far I get. I’ll post a link to the result.

I did preliminary tests using the debug configuration. I connected the generator to one input and the oscilloscope to the output as depicted in an image. It didn’t work unless I added a wire to the ground. I then was able to view expected signal and adjust gain, but the signal was a little bit unstable. Unfortunately it didn’t work with the coil. I see what looks like white noise whose amplitude doesn’t change when adjusting the resistor controlling the gain. I was expecting I would see 50Hz noise. I don’t know if I should work in differential mode or not. I tried it without success.

I have another coil connected to a 100W audio amplifier and the generator that I can use to induce a varying magnetic field in this coil. I can then use this as a reference signal and can vary the intensity and frequency. I already tried it without amplifier and I could see the signal with my oscilloscope.

Edit 2: I have translated the documentation of the AD620 module. It is available here. It contains my email for private contact if you want.

AD620 amplifier module

In the mean time, I found more information on the expected signal amplitude in an old french patent. A patent is not a blue print for engineers and there is uncertainty on the validity of the information that it provides. That’s the best info I have so far.

The signal to amplify is obtained from a coil. The coil is put close to a liquid that is claimed to generate a varying magnetic field. The coil is described to be 300 Ω and is a coil from an "old" phone microphone. The internal diameter of the coil is 6mm, the external diameter is 16mm, the length is 6mm and the core is made of soft iron. No wire diameter or number of turns are specified.

The signal to amplify is a varying voltage at the termination of the coil.

The inventor specifies that the coil is connected to an amplifier-preamplifier with the following characteristics:

  • bandwidth: 10Hz - 20 kHz
  • gain: 10 to 100 (!)
  • input sensitivity: +/- 100mV.

If that is correct, I won’t need a x10,000 gain. But I’m not sure the coil I have is appropriate since it doesn’t match exactly the specification which are incomplete. I targeted 300Ω at 1kHz with 2000 turns and a 0.1mm wire. The impedance of my coil may be too high and the wire too thin. I don’t know the frequency used for the inventor’s impedance specification. What is sure is that it is a mike coil which is for voice acquisition. The inventor connects the coil to the mike input of a PC sound card. This is what I will also have to do at some point. For now my goal is to view the signal with my oscilloscope and check with it’s FFT that I see the expected signal.

The inventor didn’t spent much time investigating and optimizing the coil. A friend electric engineer developed the system for him. It apparently worked and the inventor spent all his time experimenting with it.

What would be great is if you could help me to make the AD620 module work and amplify the signal I get with my coil. Should I move this to another question ?

I would like to add that it would be better if I could use commodity components instead of this AD620 (e.g. a microphone preamplifier). If the experiment works it would be preferable that it is very easy to reproduce as cheaply and easily as possible.

  • \$\begingroup\$ 50 uV is the AD620 DC offset. With AC coupling you'll be able to get resolution down into the noise. What's the geometry of the magnetic field emanating from the Eppendorf? That will govern where the coils should be for the best output. Putting ferrite cored coils 'around' the Eppendorf sounds futile. Designing a magnetic circuit to match the geometry of the field is what's needed. What causes the field in the Eppendorf? Is it some spontaneous internal vis viva, or a PPM ringdown after an external field has been removed? Ultimately you're limited by thermodynamics. \$\endgroup\$
    – Neil_UK
    Commented Dec 16, 2020 at 16:15
  • 1
    \$\begingroup\$ Most engineers will be able to understand what you mean, but the common term in English is "voltage"; "tension" is a fairly archaic word for it. Anyway, what's the magnitude of the field, what counts as faint? Microteslas? Nanoteslas? Picoteslas? \$\endgroup\$
    – Hearth
    Commented Dec 16, 2020 at 16:18
  • \$\begingroup\$ Can you depict, where the oil is? Why the filed wold be AC? Why would you wrap the coil around the object? Have you considered the Helmholtz setup? \$\endgroup\$ Commented Dec 16, 2020 at 16:52
  • 4
    \$\begingroup\$ Magnetic fields from liquids and " health scientists who don’t give all the relevant technical details in their article and patents" sounds very much like homeopaths. \$\endgroup\$
    – JRE
    Commented Dec 16, 2020 at 18:10
  • 1
    \$\begingroup\$ Regardless, with the signal levels you are looking at, proving the source of the field could be difficult. You'll need to protect your equipment and the coil from the influence of other (electro)magnetic fields. \$\endgroup\$
    – JRE
    Commented Dec 16, 2020 at 18:12

2 Answers 2


But these devices are advertised for a minimum voltage resolution of 50µV at best if I understood correctly.

The front page of the data sheet says this: -

50 μV max, input offset voltage

That shouldn't be confused with minimum resolution when measuring an AC signal. Sure the DC output voltage might be 50 μV x gain and, if gain is 10,000 then you will see an output offset voltage of 0.5 volts but, that is a static voltage; your "wanted" AC signal will be superimposed on that DC offset and, it will still be properly represented.

However, you should be aware of gain imposing a limitation on your signal amplitude at 10 kHz: -

enter image description here

AD620 data sheet.

I would consider using two devices; one as a front-end with a gain of 100 and a secondary op-amp with a gain of 100 following it. You should also be aware of the noise specification.

For instance, the AD620 has a noise specification (\$e_{ni}\$) of typically 9 nV per square root of bandwidth. If your bandwidth is 10 kHz then your equivalent noise bandwidth will be a little bigger at about 16 kHz. This translates to a signal noise of 9 nV x \$\sqrt{16000}\$ = 1.14 μV RMS. This is amplified by 10,000 to become an output noise of 11.4 mV RMS.

Being practical means that this will be equivalent to about 75 mV p-p: -

enter image description here

Will your "wanted" signal be enveloped? Only you can say but there are better devices and I would probably use a low noise op-amp instead of an InAmp like the AD620. You should be able to get this noise about 5 times smaller with a much better op-amp.

I would like to know if I can compensate this limitation by using a coil with a stronger amplification factor

More turns produces a greater induced voltage for a given changing value of flux but, the limit case of many thousands of turns may cause a resonant peak (due to parasitic capacitive coupling between layers of turns) that affects the gain.

Another naive question is if I could also increase the signal amplitude if I put 2 to 5 coils in series around the Eppendorf, each one with a ferrite core.

That's pretty much the same as increasing the number of turns.

Then you could bring in the really big guns. If you know what your signal frequency is then you can apply a band-pass filter to remove a lot of the noise that might dog your measurements. For instance this circuit: -

enter image description here

  • R = 10 kΩ
  • L = 1 mH
  • C = 1 uF

It has a resonant frequency of about 5 kHz but it has very steep skirts like this: -

enter image description here

This Interactive BP filter calculator will allow you to calculate different filter values for different centre frequencies.

I estimate the noise bandwidth to be about 300 Hz and that is a significant improvement over 16 kHz previously mentioned. I reckon noise would reduce by over 7 times.

Given that I'm suggesting you to use a two stage amplification system, you should put the filter between stage 1 and stage 2. In comments I mentioned putting at the end of the signal amplifier chain but I'm changing my mind a bit. You could also use a graphic equalizer for removing out of band noise. If you have one, use one.

I would be glad to make the amplifier myself, but it doesn’t sound realistic. I would have to make a plan of a PCB card which is already a science in itself, and submit it to a factory. Then debug the card, which is also beyond my competence.

You can get an el cheapo LM358 amplifier module with a gain of 100. I believe that they might just do the job when connected to the back of the AD620 module via the aforementioned filter: -

enter image description here

They're not that great but it might give you enough of a positive result to think about designing this amplifier with a more professional specification.

  • \$\begingroup\$ Thank you very much this answer. Thanks for the low pass filter schema. Should I put it between the coil and amplifier or between the amplifier and the oscilloscope ? I guess it’s before the amplification. Where could I find a low noise op-amp amplifier with a gain of 1000 or 10,000 ? There are plenty schema on the net, but I can’t build it myself. Any suggestion ? \$\endgroup\$
    – chmike
    Commented Dec 16, 2020 at 17:53
  • \$\begingroup\$ First, build a two stage amplifier with stage 1 gain at 100 and stage 2 gain at 100. Overall gain is 10,000. A suitable front-end op-amp with really low noise might be the AD8597. Put the filter between output of 2nd amplifier and oscope. If you can't build it then that is a problem but, how would you build an AD620 amplifier? @chmike \$\endgroup\$
    – Andy aka
    Commented Dec 16, 2020 at 17:59
  • \$\begingroup\$ @Andyaka I would have bought this card fr.aliexpress.com/item/32889722488.html. I wouldn’t have made it myself. I would be glad to make the amplifier myself, but it doesn’t sound realistic. I would have to make a plan of a PCB card which is already a science in itself, and submit it to a factory. Then debug the card, which is also beyond my competence. I can do that with software. How could I solve this ? I could pay to get it made, but who ? \$\endgroup\$
    – chmike
    Commented Dec 16, 2020 at 18:09
  • \$\begingroup\$ @chmike I guess you could use that but run it at a gain of 100 then, get some cheap but half decent audio amplifier and amplify the output by another factor of 100. You should be able to find some cheap audio amp that can deliver a gain of 100. \$\endgroup\$
    – Andy aka
    Commented Dec 16, 2020 at 18:13
  • 1
    \$\begingroup\$ Sorry, I thought I did. It's done now. \$\endgroup\$
    – chmike
    Commented Jan 6, 2021 at 16:44

10 kHz is audio, and your coil is not different from a dynamic microphone, so if you don't want to build a circuit the easiest solution would be to use a low noise microphone preamp. This will probably be cheaper than a lab-grade instrument, and these preamps are usually specified for noise so you know what you're getting.

Another option would be to use a low-noise opamp. Since DC source impedance is low (it's a coil) I don't think you need an opamp with low input current noise, therefore you can use a bipolar input opamp. I recommend ADA4898, its input noise is just ridiculous, and it has high bandwidth. This means you must do a proper layout with proper decoupling caps, but on the other hand it means it'll have plenty of loop gain to have a gain of 100 without meaningful distortion. It's basically an easier to use version of the AD797. You can also use LT1128.

If you need a gain of 10000, it is better to use two stages with AC coupling between them, that makes better use of the available gain-bandwidth product, and avoids amplifying the DC offset by such a huge amount that it becomes a problem.

Note I don't think you need an instrumentation amplifier. If you worry about noise being picked up by the cables, the simplest is to use no cables and just solder the coil to the pcb. Since the cable will be on the output, with much higher level signal, signal to noise ratio will be much less of an issue.

If you want even less noise, you can build this preamp, you'll have to buy the schematic but it's only 3 euro. I've got one, and it delivers the goods, but you don't really need this.

Note that for microvolt signals you have to be really careful about power supply noise. Personally I'd just use two 9V batteries to make a +/-9V supply. Microphony is important, especially in capacitors. Since your input signal has no DC voltage, it doesn't need to be AC coupled so there is no need for an input cap. The first cap should be at the output of the first opamp, where the signal is already amplified and thus it is less critical. The least microphonic caps are basically electrolytics. As far as resistors are concerned, don't use thick film as these have extra noise, use thin film or Vishay MMA0204 MELF resistors.

Another problem may be electrostatic fields picked up by the coil, but you can shield it (don't make a shorted turn).

Mains frequency magnetic field will also be a problem. You can arrange a 50/60Hz notch filter, but it would be easier to do that digitally once the signal is acquired.


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