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Why didn't we involve the 4 Ohm resistor while doing the mesh i2 ?

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  • \$\begingroup\$ A mistake? Slip of the pen? \$\endgroup\$
    – G36
    Dec 17 '20 at 20:52
  • \$\begingroup\$ I have no idea, I thought maybe it's because that part is an open circuit, so \$\endgroup\$
    – JuanDoe
    Dec 17 '20 at 20:56
  • \$\begingroup\$ No, what is the answer for the Thevenin voltage? And \$V_\phi\$ is? \$\endgroup\$
    – G36
    Dec 17 '20 at 20:58
  • \$\begingroup\$ Vϕ is 20V, Voc is 120V ,i source(when you make it a short circuit)=40 ohm, Rth is 3 ohm, Vth is 60 Volt \$\endgroup\$
    – JuanDoe
    Dec 17 '20 at 21:05
  • \$\begingroup\$ I meant, what is the "parameter" for \$V_\phi = 4\Omega \times I_1 \times What\$ \$\endgroup\$
    – G36
    Dec 17 '20 at 21:07
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Your first loop equation is correct. For the dependent source, only the i1 current needs to be taken into consideration. We can use the outer loop for finding Vth.

eqns

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