How does changing the inductance, capacitance and load in a buck or boost converter affect the circuit?

Before anyone calls me out, yes I am asking electronics related questions due to homework but honestly I am able to answer some of them. There are just some that I need StackExchange insights. For others, they are admittedly things that I don't know or cannot search easily.

My electronics professor is currently teaching DC-to-DC converters. He decided to drop us some theoretical homework and just postpone the experiment. He gave us some questions. This is one of those that I need more insight on.

I don't have quite a good grasp yet on the topic but I do know that buck converter causes a step down in the output voltage while boost converter causes a step up in the output voltage.

I would like to know how changing values in the inductor, capacitor or load can affect in particular other parameters such as output voltage and probably how they affect the circuit in general.

By the way, you guys can refer to this Stack Exchange link as it talks about changing load in a buck or boost converter and how it affects the output voltage. Why does voltage change with load in buck/boost converters?. You can use it when explaining if you think part of your answer might end up being a lengthy explanation of something that is there.

Why does voltage change with load in buck/boost converters?

I've also referred to that link because I have a separate question which asks "How does the duty cycle and input voltage in a buck or boost converter affect the circuit?" and I did refer to the formula relating input voltage, duty cycle and output voltage and mention how it only applies for continuous conduction mode. After that question comes the one mentioned in this topic which focuses on the inductance, capacitance and load instead.

Edit: Here is a more accurate basic buck topology.

• Have you studied the flyback converter - the buck-boost in your question is conceptually exactly the same. – Andy aka Dec 20 '20 at 11:05