Imagine a 1.5V battery.
- Before the battery is connected to anything, is there any voltage on either end? That is, is there already a build up of negative charge on the anode? OR is it that when the battery is connected to a circuit electrons easily moved from the anode enters the conductor and push charges to the cathode creating a voltage difference escalating the process to a potential difference of 1.5V?
I assume the end already has a charge buildup creating an E-field but because of the material(e.g. air) it's too weak to displace the electrons.
As a conductor is connected the E-field in the conducting material is strong enough to Force the electrons through.
If there are 2 1.5V batteries and the anode of one is pressed against the cathode of the other why doesn't current flow? One end is positive and the other is negative and the ends are conducting?
If there are 2 1.5V batteries connected in SERIES and connected to a circuit the potential doubles. Now I can kind of understand why as the second cathode has an additional set of positive charges increasing the E-field. But then why do the two batteries even have to be connected, wouldn't it be enough for them to be close to each other and just connect the cathode of one to the anode of the other?
So then I assume there is no charge until the ends are connected to a conductor. But that leads back to question 2. The anode of one connected to the cathode of the other doesn't create a current?
- What happens if the two batteries are not connected in SERIES but one cathode is connected to the others anode, is there a current but with still 1.5V potential? It shouldn't have to be a closed loop as electrons don't go round and round, just from lower potential to higher potential.
It's all very confusing for me.