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I have a background in physics and I'm trying to get into antenna theory for a personal project. I had some questioning about standing waves, and reading Standing waves in Dipole antennas and the enlighting answers of @Vinzent, I would try to summarize and to point out some yet not-so-clear points:

The antenna is a continuation of the feed line coupled with vacuum by mean of an altered geometry. This alteration bring in impedence and reactances that can be modeled by an RLC circuit. Such circuit are know to resonate and store energy exchanging it between the C and the L component, the role of which in the antenna is played by E and H components of the induction field and by current and voltage standing waves. The resistive losses and radiative losses are restored by the feed-in voltage and current which are in phase and thus actually carry power.

What I still don't understand well is why the waves reflected from antenna tips do not propagate back across feed line. Maybe an impedance missmatch, as seen from antenna towards line, prevents this to happen? If so, such mismatch would not simmetrically affect line signal and reflect it back to source? Also, the statements: Resonance however is not to be confused with standing waves. I would advise you to read up on resonant circuits, I think it can help you understand what happens to the wave inside the antenna (it is roughly equivalent to a parallel RLC circuit) are highly confusing. A standing wave is a physical phenomena that occurs everywhere there is a oscillations susceptible closed system, bounded by some boundary conditions. Resonance is the response of an oscillating system to some forcing term. Eg: A guitar string oscillates by mean of standing waves and can be in resonance with a sound source. Both these aspects are present in an antenna. The equivalence with an RLC circuit can be invoked because of some real analogy, but the antenna is a physical system and thus each statement, Eg. "standing waves do not propagare back to line" must have a physical explanation, which, at the moment, I was not able to find even in literature.

Thanks for any comment.

As pointed out by @user287001 the wave equations must be solved simultaneously around the whole rods to get any idea what happens. this is clear. Also, you are affirming that the standing wave is a consequence of the solution of this equation (precisely the induction field part) not of the reflection by antenna tips. This make sense. However, I would like to note that if the standing wave assumption works good in describing the current, voltage and the field also outside the antenna (e. g. there is a derivation of the radiation lobe for the short dipole based on this) probabily it is because there is really a standing wave in the antenna, so there must be a reason why this oscillation does not propagate back to line, and the only possibility seems to me an impedance mismatch towards the line. This is not asking a miracle, is simply asking physical consistency to a model.

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  • \$\begingroup\$ Have you considered that an antenna is just an impedance transformer from circa 50 ohm to 377 ohm (the impedance of free space). \$\endgroup\$
    – Andy aka
    Jan 1 at 10:36
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    \$\begingroup\$ That's, in my humble opinion, the conclusion one draws at the end of the problem, not an explanation of it. \$\endgroup\$ Jan 2 at 17:05
  • \$\begingroup\$ The sentence "Precisely the induction field part" wasn't in my writings. \$\endgroup\$
    – user287001
    Jan 2 at 21:11
  • \$\begingroup\$ No, but since the induction field is the non propagating part, just oscillating and storing energy, as standing waves do, it's a reasonable assumption of mine. I don't have proof, though. \$\endgroup\$ Jan 4 at 16:56
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Radio engineers meet often cases where a reflection happens at the end of a transmission line, but the signal still doesn't reflect towards the source, the structure is a matching stub which is inserted to direct all fed signal to the load which alone would be mismatched with the feeding line.

The antenna which isn't big when compared to the wavelength must be seen as one item, there's no parts that coming waves could see separately. The idea "wave reaches at first the feeding point, propagates to the ends of the dipole rods and reflects back towards the feeding point " is a total misconception. How? Dipole rods are no more 2 parallel wires which guide the wave to propagate along a transmission line, the field around the rods must be handled as one unit and the wave equations must be solved simultaneously around the whole rods to get any idea what happens.

The known solution is that the wave spreads to the space and virtually nothing returns back to the feeding line if the line is matched to the dipole and the dipole is in tune at the used frequency. That result cannot be found otherwise than by solving as one piece the behaviour of the wave in the whole antenna and the space around it.

Many radio antenna books show how the radiation field of a dipole is derived by assuming a standing wave like sinusoidal current distribution along the rods. That's ok engineering approximation for many practical purposes, but the exact current distribution along the dipole rods is a little different and it cannot be derived properly without solving the wave equations in the space around the rods.

The fields around the dipole can be divided to 2 parts:

  • radiating wave
  • oscillating near field, which can have reactive power in VA:s much bigger than the power of the radiating wave is in watts.

That big difference gives some justification to the idea there's a standing wave in the antenna. But the standing wave like behaviour is caused by the fact that virtually nothing returns to the feeding line, its not that there's a standing wave but some miracle (=explanation you are waiting for) stops the reflection to return to the feeding line.

ADD: The matching stub I mentioned in the beginning can be engineered with circuit theory and by following the total admittance of the loaded line with Smith's chart. One searches with the chart where the total admittance of the loaded line is 1/Zc + Yj where the real part 1/Zc is just the inverse of the line impedance and the imaginary part Y is what it happens to be. Then one inserts to the found place in parallel with the line the shorted or open ended stub which has total admittance -Yj. That makes the stub+the rest of the line+the load matched - no reflection to the source end, no matter there's standing wave in the stub and in the section between the stub and the load.

Actually the stub makes the backwards wave towards the source impossible. The engineering calculation happens in the world of voltages, currents, impedances and reflection factors, it doesn't a all care the actual E and H fields in the space around the wires.The working of the construction definitely happens in those fields, but fortunately there's quite good correspondence between the vector field effects and the circuit theory version.

We do not have proper circuit theory distributed element model for dipole rods. I guess you wanted something like inductor, capacitor and loss resistor ladder (=like the TEM transmission line element) which has a loss resistor in series with the inductor. In this case the capacitors decrease towards to rod ends and the resistors present the losses caused by the radiation. Assuming that model exists you hoped there's perfect matching achieved in the feeding point just like in the mismatched transmission line is tuned with the stub.

Unfortunately such model isn't well known - at least I haven't seen it. And scientifically it would be nonsense as long as nobody has proved the properly solved fields obey that model. In TEM transmission line theory mathematicians have found that Heaviside's ad-hoc LRC ladder element approach fits with the properly solved E and H fields.

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  • \$\begingroup\$ Reality is always more complex. The reminder deserves +1 \$\endgroup\$
    – Andy aka
    Jan 1 at 13:12
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Note that an ideal feedline is balanced, thus has no net current or voltage and thus no EM field, as all the equal an opposite currents cancel out. Thus any reflection into the feedline is cancelled by an opposite reflection. e.g. the field equations for the feedline in isolation should produce a result netting to zero. And thus those 2 cancelling reflections can be treated as if they did not exist, or as if the feedline and RF source had zero dimension, and any standing waves or RF current passed right across the feedpoint of the antenna without any reflections out of the antenna wires or system into the balanced pair of feedline conductors.

Now, a non-ideal feedline, due to common mode currents or unbalance EM field coupling, that's a different animal.

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  • \$\begingroup\$ Note that an ideal feedline is balanced, thus has no net current or voltage and thus no EM field, as all the equal an opposite currents cancel out. and thus we have an energy transport without current or voltage or even EM field. A miracle. \$\endgroup\$ Jan 15 at 10:37

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