The image represents a 4x3 memory.Build a 2x8 memory.
\$\begingroup\$
\$\endgroup\$
11
-
1\$\begingroup\$ And? Did you build it? Did you try building it? \$\endgroup\$– Eugene Sh.Jan 7, 2021 at 15:47
-
\$\begingroup\$ no i'm stuck,I dont know how. \$\endgroup\$– BjoniJan 7, 2021 at 15:52
-
3\$\begingroup\$ Can't you identify the pattern on the schematic? What "4" corresponds to? What "3" corresponds to? What you need to do to change these to "2" and "8"? \$\endgroup\$– Eugene Sh.Jan 7, 2021 at 15:54
-
2\$\begingroup\$ Sorry, we won't do your homework for you. You say you are "stuck" but it doesn't look like you even tried. Show us that you have made a substantial effort to solve this yourself, then come back if you have a specific question. \$\endgroup\$– Elliot AldersonJan 7, 2021 at 15:57
-
2\$\begingroup\$ Bem not homework without any effort in the exercise(s) \$\endgroup\$– The Force AwakensJan 7, 2021 at 16:01
|
Show 6 more comments
2 Answers
\$\begingroup\$
\$\endgroup\$
0
This may or may not help you.
First, redraw the schematic so that it is less convoluted.
Remove the zig-zags from the input and output lines.
Find common "blocks" and spread them out to make the schematic less "dense".
Use color to clarify some of the signals.
You'll get something like this.
\$\begingroup\$
\$\endgroup\$
I build your circuit with an online simulator. I think it is best to use a simulator to evaluate your approach.
https://electra.academy/simulator/?shared=47c57dd2eb0c93c0d9aeb38fabd82c5e772158a6
This is a good starting point to go into the right direction for your solution. The "address decoder" is in you case pretty simple. It is only a simple on/off switch. You have only two memory cell. In this case only two states are required. 0 and 1
The rest it pretty simple.
