consider single phase two pulse semiconverter asymmetric configuration.
Note the high value of inductance L1.
a be trigger angle of SCR, which is greater than
t = arcsin(E/Vs). Now the SCR will work from
pi-t and maybe beyond if current does not fall below holding current. But would not the diode
D2 turn off after
pi-t because voltage falls below zero?
Why does using a high value of inductance allows current to flow in
pi-t and upto
pi+a ? Does the emf
E play no role in switching off the diode?
What actually happens after
pi+a? I assume that D3 cannot start conducting before
SCR4 cannot start conducting before
pi+a. So where does the inductor current go?