Colpitts oscillator not functioning

Question

^{simulate this circuit – Schematic created using CircuitLab}

I don't understand how the circuit works .I know it is a Colpitts oscillator but the part where I get confused is that in the video on youtube it says we can set Ve = 1/2VCC however I don't understand how this can happen since we don't have a base resistor and the emitter resistor will try to draw as much current as the emitter current but this isn't possible because the voltage drop on the emitter resistor cant be more than VCC . I am not sure if this circuit can work based on that I wrote earlier.Can somebody explain it to me please?

Answer 1

If R2 is the same value as R3 then they will project a DC voltage onto the base of about 50% of Vcc. The emitter will be about 0.7 volts below that. The emitter current will then be approximately half Vcc minus 0.7 volts divided by Re.

I know it is a Colpitts oscillator but the part where I get confused is that in the video on youtube it says we can set Ve = 1/2VCC

By making R2 a little smaller than R3, the base voltage can be adjusted to be half Vcc plus 0.7 volts thus, the emitter voltage will be half Vcc.