Motor loaded at percent %

For an 3 phase AC motor, the full load current of a 3 phase motor is: $$I= \frac{P(KW)}{V*\sqrt3 *Pf}$$

when I was studying power factor correction, I came across some concepts like motor motor loaded at 25%, 50%, 75%, 100%.

What means a motor loaded at 25%, 50%,... and how the calculations for example of the current change in this case.

• Your equation should also include a term for efficiency. Feb 21, 2021 at 8:45
• It's percetage of the motors rated (nominal) power. The percentages are valid for current also (or very close).
– user208862
Feb 21, 2021 at 9:08
• Ask yourself what load the motor is driving and how much torque that load takes, compared to the motor's full load torque rating. Since it's an induction motor, you can focus on torque and current rather than power, with reasonable accuracy. Feb 21, 2021 at 13:29

The equation should be $$I= \frac{P}{V*\sqrt3 *Pf *Eff}$$