Here, all the initial conditions are : i1(0-)=0A and i2(0-)=0A When t≥0, the current i1(t) and i2(t) starts flowing. From my assumption, steady state value of i1(t) is 10A but what happens to i2(t)? Applying KVL, 10=i1(t)+di1(t)/dt - di2(t)/dt And i2(t)= di1(t)/dt-di2(t)/dt. The time constant τ of this Circuit is 2 sec. If at steady state di1(t)/dt =0 then di2(t)/dt=0;then i2(∞)=0A. According to my calculation, i1(t)=10-10e^(-0.5t) but what about i2(t)?How to figure out the i2(t) equation? Is it all zero? Please help me out with i2(t)? I simulated the circuit and got these for 60Hz... Both of them are same in simulation graph. How is it possible? Also this circuit can not be run at very high frequency. Please help me with i2(t).
I decided on something similar but different. Can you see why R/Lin= 2ms ? when Lp=1 , R=1
Your AC simulation lacks some spec so must be different from your expectations. What is Zin(f)?