# Negative terminal of a sine generator simulate this circuit – Schematic created using CircuitLab

I had this problem where the anode of a diode was connected to the negative terminal of a sine generator.

I wondered how it functions so that I can get the current that goes through the diode.

If lets say Vi(V1) is the positive terminal of the generator, would the negative one have the opposite wave, as Vo = -Vi?

I know it's a very basic question but I was surprised to find out that most of my university's students didn't knew the answer to it.

• What sine wave generator? What does its manual say? – The Photon Feb 25 at 19:04
• If you hit the CircuitLab button on the editor toolbar you can draw the complete circuit and simulate it. Important: You need to add a ground symbol and connect it somewhere in your circuit. Hit "Save and Insert" when done to add in the schematic so we're clear what we are discussing. – Transistor Feb 25 at 19:06
• funny thing about a sinewave is that the negative terminal keeps changing... – user16324 Feb 25 at 19:10
• Not sure what the question is. If it is about current through the diode, then you first have to know the peak-to-peak amplitude of the sine wave. – AnalogKid Feb 25 at 19:39
• You didn't add the GND symbol so, I guess, you didn't simulate either? What is V2 for? – Transistor Feb 25 at 20:02

## 1 Answer

You have (in the two voltage sources) an output that is Vout = $$\5\sin(\omega t)-2\$$ relative to ground.

The negative terminal of V1 is 0V by definition since you connected it to ground.

The positive terminal of V1 is $$\5\sin(\omega t)\$$, which is the same as the positive terminal of V2 since you connected them together. $$\\omega\$$=2$$\\pi \cdot1000\$$, of course.

And the negative terminal of V2 is the output so as in the first sentence. It's 2V less than the positive terminals of V1 and V2.

• Thanks a lot, so if we connect the ground to the negative terminal of V2, the output of the negative terminal of V1 would be Vout = -5sin(ωt)+2, thus it graph would look like shown in the linked picture right ? drive.google.com/file/d/14g2HP1MGMKQ3BOqATbX5BHJbFpsLm6K9/view – Ayman Feb 26 at 11:30
• That looks correct. – Spehro Pefhany Feb 26 at 12:22