After all these years I am back to the start position of how capacitors work. I don't know to laugh or to cry. Okay even before that. When I hook up two wires, one on each terminal of a 12V DC battery and I measure the voltage difference at the end of the wires, it reads 12V. That goes without saying.
Now we learned, at least I seem to have that no current of charges moves at all in an open circuit. So what moved from the battery to the end of the wires? If I place an ammeter in any of the two wires also before I test the voltage at the end of the two wires, I must not read any current in the ammeter but I assume I would read volts in the voltmeter.
Since I certainly read volts, it must imply that energy ( I had to throw in that word) moves without any charge movement, unless charges actually do move in an open circuit.
Capacitors by actual design is an open circuit no matter how close are the plates. To my understanding, that is the whole idea, not to allow charges to move through.
So you can see what my mind is looking at here. And capacitors are not like a battery where the plates are connected by the fluid/electrolyte in some respect.
( I realize also that Antennas are basically open circuits....)
Furthermore current of charges is at a maximum in a capacitor and it is described as a short circuit assuming no resistors are there.
Can anyone explain this without using formulas? Thanks in advance.