When there is no load connected to the secondary, E is equal to U, and no current flows in an ideal transformer. Now if we connect a load on the secondary of a transformer, the primary will draw a current because E<U (temporarily), why when E gets equal to U the transformer will still be drawing a current "I1" from the mains, doesn't that violate the reason current started flowing in the first place?
I know that the secondary field must be counterbalanced at all times by the primary field, but I have a confusion about the fact that even though there is no potential difference because E=U there is still a current flowing.
Can anyone explain that? And please correct me if I am making any thinking errors.
Image from: DC Machines and Transformers by K Murugesh Kumar