If you simulate your circuit, you will get this result:
As you can see, the current through the bases of the transistors is almost 40mA and the current through the 1k resistor is less than 1mA. The is because the base emitter paths of the two transistors are appearing across V1. Because of this, the full 2.5V appears across the base-emitter paths of the two transistors and results in a very large current flowing through them. Now, because there is current flowing through the bases of both transistors, both transistors are actually on and are shorting V1, which is why you are only getting a sub 1mA current flow through the 1k resistor.
If you take a look at the current flowing through the collectors of the BJTs, you will find that it is nearly 700mA!
So your configuration of the transistors shorts the power supply (V1) irrespective of what the control signal is doing (V2).
But if you swap the positions of the two BJTs, you will get a buffer. Also, such a configuration can be used to drive MOSFETs.