# Why does the current enter the negative terminal of this element and it is still absorbing power?

Hi there, I am learning the kirchhoffs-laws, according to the passive sign convention if a positive current enter through the positive terminal of an element and exits out of its negative terminal, then the element is dissipating power.

So, in this diagram the current enter through the negative terminal element with 3 ohms resistance. The calculation shows that the voltage across it is the same sign as the voltage across the 2 ohms resistor. Why do they have the same voltage sign although the current enter through different polarity of terminal, is there any element that has such properties in real life?

• Conventional current enters on positive side of resistor, but KVL can be done by just picking polarities at random. This is the case here. Answer will be negative, which just means polarity assumptions were wrong. Commented Mar 31, 2021 at 13:48
• By the way, this would be the situation if the "element" was a true negative "resistor" (circuit) with -3 ohm resistance (the so-called VNIC converter). It would act as a proportional negative voltage source producing voltage v2 = -3i (adding it to 20 V) instead consuming a voltage drop v2 = 3i (subtracting it from 20 V). Commented Mar 31, 2021 at 17:46