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The example problems I'm seeing in the book gives me nice numbers where the size of the ram can easily fit into a power of 2, but this one doesn't.

The original question: enter image description here

This is all I have: enter image description here

I was thinking about splitting twelve into 2^3 and 2^2 then add them but I don't know? or would I just choose which ever ram is higher or lower like 12 is in-between 8 and 16?

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  • \$\begingroup\$ How do you fit something into a box when you don't have exactly the right sized box? Obviously, you just use the next size up and live with the empty, unused space. Simple, no? \$\endgroup\$ – DKNguyen Apr 1 at 3:04
  • \$\begingroup\$ @DKNguyen true, i guess i'll go with 16G then \$\endgroup\$ – S. Coughing Apr 1 at 12:12

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