I am designing an enclosed container with 10 kWh 50 V battery in it which requires me to actively remove the heat. The battery feeds an 8.8 kVA inverter. Assume I have a load of 8 kW, which would draw 160 amp at 50 V.
One of the sources https://batteryuniversity.com/learn/archive/how_does_internal_resistance_affect_performance referred to small Li-ion and gave internal resistance of about 320 mΩ to 340 mΩ. Other sources were more academic and incomprehensible. Most addressed charging - nothing on large batteries.
If this is the case the internal heat generated would be I2 × R = 1602 × 320/1000 = 8192 W, an impossible result.
Either the internal resistance is wrong or I am using the wrong logic. How much heat would the battery create during discharge?