# Understanding Negative feedback loop circuit with an Ideal Op-Amp

The following is given as an example of a negative feedback loop in my textbook, note that the op-amp is assumed to be ideal.

However I do not seem to understand the logic behind this acting as a negative feedback loop.

Suppose if $$\V_{in}\$$ is $$\0.01V\$$ after passing through the op-amp. It should be amplified to $$\+6V\$$.

Now $$\V_{out}\$$ is $$\+6V\$$ hence the inverting input will also become $$\+6V\$$ thus the difference between the two inputs becomes $$\-5.99V\$$ thus $$\V_{out}= -6V\$$ and this process shall repeat over and over again. Would the circuit then just cycle between being $$\+6V\$$ and $$\-6V\$$ until the power supply is disconnected?

How is this considered a negative feedback, am I missing something crucial?

The op amp generates a voltage equal to the difference of the two inputs. Hence, suppose we start with $$\V_{out} = 0V = V_{-} = V_{+}\$$. Let's consider two cases.
1. The input becomes positive, $$\V_{+}=0.1V\$$ . The output is equal to the difference of the two inputs. Thus, it is equal to $$\V_+\$$, and we end up with $$\V_+ = 0.1V = V_{out} = V_-\$$.
2. The input becomes negative, $$\V_{+}=-0.1V\$$. Again, the output of the op amp is equal to the difference of the two inputs. Thus, it is equal to $$\V_+\$$, and we end up with $$\V_+ = -0.1V = V_{out} = V_-\$$.