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I read the Christophe Basso APEC 2011 seminar, about this figure I have some things I can't get it.

1.)Why should need to put the Cdc capacitor in the circuit, what's this function? to block the DC source?

2.)Why need to let Vfb at 2-3V, how to make sure it is in the linear region.

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Why should need to put the Cdc capacitor in the circuit, what's this function? to block the DC source?

Yes, it's to block Vbias thus allowing the DC value acquired on the photodiode's anode to be unaffected. Remember that this is a test circuit to characterize the opto-coupler and not a part of a real flyback controller circuit. The signal from Vac becomes superimposed onto the DC voltage acquired on the anode and allows you to characterize the opto.

Why need to let Vfb at 2-3V, how to make sure it is in the linear region.

A lot of flyback controllers operate with the opto-coupler's transistor collector at or around 2.5 volts and so this is done to put the opto in it's correct nominal operating area. It will be roughly linear for small changes in photodiode currents at this point.

However, an equally good circuit would be to use a DC voltage (controlling the bias) in series with a floating AC source with both in series with a 20 kΩ resistor feeding the anode.

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  • \$\begingroup\$ Hi Andy Thanks for your reply About the first question: Why not just add the DC voltage in there, if just need the DC value, About the second question: the optocoupler's operating voltage at 2.5V, this value if form datasheet? How to make sure I can let Vfb at 2~3V, can you use math to let me more clear? \$\endgroup\$
    – Jitter456
    Apr 14, 2021 at 18:12
  • \$\begingroup\$ You need to superimpose an AC signal on the DC bias - you can't just put a constant DC value there. The AC signal characterizes the pole frequency. The nominal 2.5 volts is because a lot of controllers when operating correctly will cause 2.5 volts to appear on the opto collector. Look up some data sheets of older flyback controllers or maybe there is mention of the particular one by Basso? @Jitter456 \$\endgroup\$
    – Andy aka
    Apr 14, 2021 at 18:47
  • \$\begingroup\$ Hi Andy It is more clear to me now. Thanks \$\endgroup\$
    – Jitter456
    Apr 15, 2021 at 1:27

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