I'm trying to figure out what the windings do when a tap change occurs on a power transformer. The picture below is my understanding of how tap changing occurs when there is an increase in load on the TX. When the load increases and the volts drop on the secondary side of the TX. To compensate for that drop, either the Primary volts will need to increase or the primary winding will need to have some of its windings removed. In my calculations I removed a percentage of the windings to compensate for the volt drop. Does this picture explain correctly how tap changing occurs? Realistically I'm sure the primary volts gets reduced a bit as well but will it reduce as much as the secondary volts on load? I understand in the real world you would have a three phase either star and/or delta connected system, I just represented it as single phase for simplicity. P.S The value 10.75KV is just an arbitrary value chosen for the Vd. Thanks.
1 Answer
When the load is increased, the voltage drops due to IR voltage drops in both the primary and the secondary.
If we ignore saturation, then the output voltage can be boosted back up to its proper level by modifying the turns ratio by either reducing primary turns or increasing secondary turns.
Doing all the compensation for varying load by tap-changing on the primary means that the flux has to increase, to compensate the IR voltage drop on the secondary. A transformer that is provided with only primary taps must be designed such that the flux is still below saturation even on the lowest primary tap with its highest input line voltage.
A technically better arrangement would be to provide a transformer with both primary and secondary taps. You would use the primary taps to control for line voltage variation, and both sets of taps to control for droop with load current. It's probably cheaper to provide one winding only with taps, and over-size the core slightly to provide headroom before saturation.