I bought a brand new lead acid battery for my motorcycle after the previous one was at the end of its lifecycle. Just to mention the battery is of the brands associated with a good quality. It was a dry model that I needed to fill myself with the electrolyte sold with the battery. It worked well after following instructions carefully. No problem.
However after some 50h of driving and forgotting park lights on the battery was drain out. Voltage was down to some 10.5V or so. No hope for starting. No problem either. Just charge the battery. I took it apart just to check the overall condition and charge overnight.
Now, I understand that such an energy drain to low voltage can damage battery but what surprised me was that 3 cells had lost a lot of electrolyte and the rest 3 cells were at specified level. Anyway I added distilled water to specified level, charged overnight and there was again enough peak amperes to start.
Next I checked the regulator (roughly) after charging by checking the system voltage and it was (at "low rpm" like 1500 - 4500, about the rpm of of the travel speed of my bike) between 13.8 - 14.5V.
Ok, maybe for that specific battery - say 14.5V - is too much. I could understand that it could cause some (or even big) loss of electrolyte. What I can not understand is why some cells - in a brand new battery - were like nothing happened and the rest were like totally dry.
I do not know if it matters but the dry cells were at positive side of battery but not the most positive was the most dry. The amount of electrolyte (6 cells from - to +) was approximately 100%, 95%, 100%, 55%, 20%, 75%. These amounts just roughly describe the amount of electrolyte needed to satisfy the specified level average.
Is this kind of wearing in such a short time usual or should I return this battery to the dealer?