I was going through the datasheets of a few active PFC controller ICs (like this: https://www.ti.com/lit/ds/symlink/ucc28019a.pdf?HQS=dis-mous-null-mousermode-dsf-pf-null-wwe&ts=1619350669153&ref_url=https%253A%252F%252Fwww.mouser.in%252F) when I noticed something odd about the way the switch current is sensed.
Because of the location of the current sense resistor, two things happen: the load current gets added on to the switch current and the voltage across the current sense resistor is negative, as seen by the IC.
As I scrolled through the datasheet, I found the functional block diagram of the IC.
You can clearly see that the sensed current is fed to a -1x amplifier!
So my questions are:
If the voltage across the current sense resistor, which is negative, is fed to a -1x amplifier, then why sense it in that manner instead of doing it like this:
I would like to build a PFC circuit, but at a low voltage (like 24V AC) for safety reasons (I have zero experience building high-voltage circuits). These ICs are designed and optimized for mains voltage applications, so will it lockout at low AC voltages or will it still function normally?
3)
Could I just use a regular boost converter (without the input filter cap) to perform PFC, or do I really need to use a dedicated PFC chip for this?