Given this circuit I would like to know how can I find it's transfer function.
A method I've considered was to use Node Equations on nodes 1 and 2 , and I have a few things that I don't find clear :
- why do I have to introduce an additional equation with \$V2=0\$ ?
- Once I find the transfer function in form of \$H(s) = {\dfrac{R1}{R2+Ls+CR1R2s+CLR2s^2}}\$ I must calculate \$Vu(t)\$ with \$V1=10+cos(t)\$ , the solution states that \$Vu(t)= H(0)*10 + Re[H(j)*e^{(jt)}*1]=-10-{\dfrac{1}{2}}{sin(t)}\$ How does one achieve this result and first of all how does the \$Re\$ part of the transfer function is calculated ?
Thanks a lot for any insight provided.