I am using this LM63625 buck converter.
- Input Voltage = 16V max
- Output Voltage = 3.3V
- Output Load Current = 0.45A
- Switching Frequency = 2.1MHz.
I would like to calculate the maximum voltage across the R0202 20ohm resistor.
From the absolute maximum rating of the table, I find the maximum voltage across the CBOOT and the SW pin will be 5.5V.
If I use this voltage and substitute in the formula, 5.5V * 5.5V / 20ohm = 1.5W. I get 1.5W. But the resistor package is 0603 which has a maximum power dissipation of 0.1W.
How can I calculate the maximum voltage across the resistor?