I wanted to make sure I had the correct view on this circuit.
From my understanding D1 and D2 are input protection diodes that clip the input to prevent any large voltage differences to damage the input stage transistors.
In this configuration where J4, J2 are closed and J1, J3 are open, is this circuit an inverting amplifier, or is it a differential amplifier?
The reason I'm confused here is because during say a negative cycle only D1 is forward biased, but doesn't the input get split between non-inverting and inverting input (same for positive cycle where only D2 is biased?) Or does the signal just go to ground since that is what the non-inverted input is connected to?
Sorry if my question seems silly just haven't been able to find a similar example to this (some of my dad's old work but he's not around.)