I've been playing synthesizers for a while and I'm trying to understand their math and electronics better.
The sawtooth is one of the three common waveforms on most subtractive synths. The waves are generated by one or more VCOs and are modulated through LFOs and other sources, and we finally use some filters to remove certain frequencies and get the desired sound. I more or less understand the way these filters work, however what I don't understand is how does a sawtooth wave come to have any harmonic content at all? They way I see it, there is nothing there to be filtered except for the wave's fundamental frequency.
I'm assuming the answer to this depends on how the wave is built. If it's built additively by summing up different sinusoids then I can see how the different "frequencies" are present. However, per my understanding, we normally don't build an "analog" waveform like this, we rather slowly charge up a capacitor and then discharge it to get a ramp-like wave.
Now I know that this shape can also be mathematically "approximated" as a summation of sine waves through a fourier transform, and the transform is applicable regardless of how the wave is built, but I don't see how the possibility of such a decomposition results in those harmonics "actually", not mathematically, being present in the wave; they were simply not there to begin with.
So the question is, how it is that there are different harmonics in a sawtooth that we can filter with filters later? Don't hesitate to correct my understanding of how the sawtooth is built in the first place and please explain the electronics as simply as possible, I've never been really good in this stuff.
Update:
I think what I find most confusing or counter-intuitive is that the harmonics suggested by the fouriers series for the sawtooth function actually exist and are not just a mathematical abstraction.