I have a circuit with a not-so-small capacitor on the supply and I need to reduce the inrush surge; as a matter of fact the power supply breaks after a while (these cinese supplies are not fun)
I followed ON Semi AND9093/D (which is in fact very well made) and come up with the following circuit:
From the left comes a 12V supply, on the bottom there is a BJT enabling the switch when the times come and on the right after the beefy capacitor there a mixed load; at the moment is still disabled but there's some leakage anyway on the right side, if only for the capacitor one.
However there is still a surprise: when I initially apply the supply there is still a surge while the load switch itself stabilizes:
I explain this as follow:
At start up everything is discharged, C12 and C13 included;
When I supply power Q1 is in conduction even if /HSGRAIL is not pulled down since the source is at supply level and the gate is still low since C12 is not charged yet (probably some leakage from somewere make it starting low, even the /HSGRAIL has some leakage of course)
The gate initial charge to the supply is slowed down since C12 needs to be charged initially, too.
However if I lower R2 to raise the charge current, R3 need to go down to maintain the FET below Vth and then C12 would need to be bigger in proportion (the sad rule about RC time constant)
What would be the best way to solve this?
- Some magic topology trick?
- A push-pull gate drive (i.e. R2 and R3 replaced by transistors) so that it actually starts charged quickly? probably would need to make it discrete since most of the integrated ones stay high impedance until supply is stable;
- Switch to an N-channel switch and a charge pump driver? (a lot more expensive but if it's the only way)
EDIT: I forgot the oldest trick in the book:
- No gate-source capacitor.
- A 'suitably big' charge resistor (refined people would want to use a inrush control NTC)
- After some time bypass the resistor/NTC with the MOSFET to reduce losses (even when the cap is charged it will be need to be recharged)
22 ohm about 1W seems to do the trick, I'm doing tests