Can I use a PNP Transistor with an Electret Microphone to get an non-inverting output for my Arduino?

Question

I'm looking to simply read the generic sound level from an Electret Microphone. I've seen a number of schematics with NPN transistors, that will provide an inverted output (~5V when quiet, ~0V when loud, linear operation in between).

Here's an example:

However, I would like non-inverted output (linear operation, super quiet input gives ~0V, super loud input gives ~5V). I realize I could easily correct for this in software, but it just seems backward to me in a way and I cannot find any examples of a non-inverting output with a PNP transistor.

Is there a reason for this beyond being uncommon? If it's possible, could anyone provide a schematic of an electret microphone and PNP transistor that will give ~0V when quiet and ~5V when loud?

Further, is there some reason why this is so uncommon, or undesirable? NPNs seem to be used much more often than PNPs, why is this?

Edit

It seems I was rather confused in what I would get as output from the NPN preamp, which would be 0V for silence, and +/- Vin / 2. Here's what I want instead:

0V when silent, ~2.5V in medium sound levels, ~5V in maximum sound levels. This could be read by the ADC easily into 'sound level' without much work at all. However, I cannot feed voltages < 0V or > 5V to the analog comparator. It looks like I want the above with an envelope detector, however that would only get me from 0V to 2.5V. How do I make it vary the full 0V to 5V, 0V being 'quiet' and 5V being 'loud', with everything in between linear?

Answer 1

As far as I understood, you are trying to make some kind of a sound level detector, which will let you detect if there is a sound with a certain volume or not. You can do this with minor changes to the schematic you have. But before that, you should understand the circuit.

Let's break that circuit down. First of all the part with the microphone.

R1 is for supplying power that is needed by the microphone and this is called biasing the microphone. A microphone generates an AC voltage, which is sometimes negative and sometimes positive and it changes most of the time. Think of a sine wave. But remember, we had some biasing to it which is a DC voltage. We have to take that out and give only the AC voltage to the amplifier. And doing this is easy with a simple, single capacitor. A capacitor does not let the DC to pass, but lets AC pass easily. We have blocked the DC portion of the voltage on the electret microphone.

Now, let's look at the amplifier itself. Imagine that there is nothing else but the below schematic:

In this configuration, the transistor is biased to be in the linear region. It is in the edge of being turned ON or turned OFF, but it is neither of it. If it was fully ON, it would be saturated. If it was fully OFF, it would be not conducting at all. But it is in the middle, which is called the linear region.

When it is configured like that, if you touch (not literally) to the base of it, creating a small change, the output will be changing largely. This is what amplification called. You can beg Google for more detailed information.

What if we combine the two circuits mentioned above. A biased electret microphone with a capacitor will output small changes with respect to sound. The transistor will amplify these small changes so they can be viewed easily:

Notice that I have changed C1 to 1uF. You can use values up to 100uF. You will probably need electrolytic capacitors. Also, notice that there is no more an output capacitor. This means that you will have an output voltage somewhere between 0 and 5 V, depending on the sound level. If you have an oscilloscope, view the waveform on the output. If you do not, try lighting an LED if the analog read is higher than, for example, 750. Experiment with different values than 750, then report me the results.

Answer 2

The common emitter class A amplifier is always inverting even if you use a PNP, the only difference is you invert the power supply polarity. If you use an audio transformer instead of a capacitor you could change the signal phase as you please. But it will probably cost more than use two BJT. In order to solve your final question anyway, you have to rectify ( even with a single diode ) the output and apply the result to a load ( a resistor would be fine ) and feed this to the arduino analog input. There is no reason to invert the signal at all.

Answer 3

This amplifier inverts the signal, but you shouldn't care for an audio signal. What you'll have at the output is AC, a capacitor blocks DC. So, you cannot say ~0V for quiet noise and ~5V for loud. If what you want is a sound level sensor, one easy way is to add, after the output cap a circuit called "demodulator" or "peak detector", easily implemented around a diode and a few passive components.

Answer 4

Simply invert the output a second time, using a 2 stage amplifier. (See this page for more info on two stage, and non-inverting transistor amplification. Very insightful)

The same value resistors and capacitors, the same 2n3094 transistor, added to the output of your existing schematic, would provide a second inversion.

_{But someone correct me if I am wrong, but your schematic shows a simple biased amplifier, so you would really have 2.5v as the quiet range, and the waveform gets larger with more sound? You will have a ±2.5v peak to peak. You would have 1v/3v as a middle loudness.}