# Transistor base current

A while ago I posted on here for some help with my circuit design. I received some great advice which thoroughly improved the original.

I made the changes to the breadboard design and the circuit ran well.

Then, on one test I left the relay activated for a few minutes by leaving sw1 closed. After a while I found the 2N2222 began to get hot. I thought maybe the resistors R5 4.7k and R6 1k are stopping the transistor being saturated, so I swapped the values round making R5 1k and R6 4.7k. When I ran the circuit again I saw the voltage drop across the transistor was less and it did not get warm at all.

The relays coil resistance is 100ohm and its a normal 12v relay which draws 120mA. The 2N2222 is rated for 800mA so there should be headroom.

Could someone advise if I have the right base resistor setup? The original idea behind the potential divider R5 and R6 was to limit the voltage into the base, as I read in the datasheet the maximum emitter base voltage was 5V. I think I'm misunderstanding something here.

This is as the circuit stands with the resistors in the swapped position so the 2N2222 runs cool.

• Maximum Emitter-Base voltage of 5V means the base voltage should be no more than 5V below the emitter voltage - but the lowest it can be in this circuit is zero. R5 is there to limit the base current to a safe level, not the base voltage (though they're obviously related). Aug 10, 2021 at 19:18
• Considering that you're driving it with an opamp capable of swinging its output very close to ground, R6 doesn't really serve any purpose here other than drawing a little extra current. It's not needed to 'help' turn Q1 off since the opamp is quite capable of taking care of that through R5. Aug 10, 2021 at 19:58
• Thank you all for your help, and explaining my misunderstanding of the datasheet regards to the emitter base voltage, and how to confirm the resistor value.. I will remove R6.
– Trev
Aug 15, 2021 at 10:37