I have a question just to check that I understand voltage regulators from a conceptual standpoint.
Say I have a power source, which delivers 8V. I need to step it down to 6V for a continuous load of 1A. Am I correct to assume that the overall circuit will only draw 1A from the power source, but 25% of that power will be dissipated as heat by the voltage regulator?
Now, I do plan on doing this, but with an L7806 voltage regulator (see page 11 for L7806 electrical characteristics), an 8V power source, and 2 motors which draw 1A each. The first problem I am seeing with this setup is that my power source is under the rated input voltage (8.6 - 19V, my source is 8V). Next, it is rated for a current draw of up to 1A (but I need to draw 2A).
So I am not sure what to do. From what I understand, if I use 2 voltage regulators to independently provide the power to each motor (each wired in parallel to the power source), then the max draw per regulator would be 1A. I still have the problem of my power source being under the voltage source though, but I may be able to fix that.
The other option I found is to use something from the RC world called a UBEC. For example, this one is rated to output 6V at a maximum of 3A, with better heat dissipation.
So what I am looking for from an answer is (1) a confirmation that I am understanding how voltage regulators work at a basic level (as well as any corrections or improvements to my misunderstanding), and (2) suggestions as to how I can achieve what I need. I would prefer to have an IC solution (like the 7806, but maybe something more appropriate for my case) because it is cheaper than the UBEC.