I noticed I have made a mistake in one of my PCBs and have connected the pull-down resistor of a MOSFET before its gate resistor (point A), rather than to the gate directly (point B, see schematic) as I assume is the correct way.

I was wondering, if not given a high signal, voltage at point A would be 0 so would that also pull the gate low or is the gate resistor going to cause trouble?


simulate this circuit – Schematic created using CircuitLab

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    \$\begingroup\$ That should be fine; the "extra" 100 ohms of pulldown resistance are less than the tolerance band of a 1% 20k resistor so no problem there. \$\endgroup\$
    – vir
    Aug 25, 2021 at 21:28
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    \$\begingroup\$ This is actually the best way if you want maximum Gate drive voltage (not a significant difference in this case, but could be if R1 was a larger value). \$\endgroup\$ Aug 25, 2021 at 21:39

1 Answer 1


100 ohms is 0.5% of 20k ohms.

It does not make a difference. Most likely you are not using 1% resistors, and even if you were, it would be off less than 2%.

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    \$\begingroup\$ I realized how dumb of a question I just asked, of course right after asking it. Effectively I'm just increasing the pull-down resistance by 100 ohms... \$\endgroup\$
    – php_nub_qq
    Aug 25, 2021 at 21:40

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