# 2nd Order Differential circuit convert to Laplace domain

The circuit is closed At t = 0 , initial state of capacitor v(0-) = 1v and inductor i(0-) = 0A.

My problem is when I convert this circuit into Laplace domain resistor become 2 and inductor become S. What happen to capacitor.

• Where's your differential equation? Commented Sep 9, 2021 at 7:07
• @Andyaka I didn't write differential equation because if I can directly this circuit convert to Laplace domain then capacitor, inductor become resistors so then easily I can use KVL to Laplace domain circuit but I don't understand to convert capacitor with initial state. Commented Sep 9, 2021 at 7:11
• Write Laplace equation first, without replacing values. this can help you. dummies.com/education/science/science-electronics/… Commented Sep 9, 2021 at 7:59
• The impedance of a capacitance C is 1/(sC) in the frequency domain.
– Bart
Commented Sep 9, 2021 at 8:32
• @Chathura1 Are you supposed to solve this as a time domain result? Looks like it to me. But I'm not entirely sure.
– jonk
Commented Sep 9, 2021 at 9:57