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I have designed this circuit and math calculation works but looking back now I feel the cap is too small may be I am making any mistake here? Can some one explain how to chose the capacitor for AC coupling the relay driver. Please do not engage in to side discussion, why I would want to drive relay with AC signal.

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Note: RLY_RUN is PWM signal, which is changed to 5V level by U63 and 100R & 47 nF acts as AC coupling to drive the U23 MOSFET. the relay used here is 24 V DC relay .

I couldn't find any design or application note on this anywhere on the Internet so far.

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  • \$\begingroup\$ Probably, your math is bad. \$\endgroup\$
    – Marko Buršič
    Sep 30, 2021 at 18:47
  • \$\begingroup\$ probably you have to implement a push-pull configuration to energise the coil \$\endgroup\$
    – gino
    Sep 30, 2021 at 19:18
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    \$\begingroup\$ 1) "math calculation works": Would you post your calculation? 2) Why does it need to be AC coupled, DC coupling should work as well? 3) What is the PWM period and duty? \$\endgroup\$
    – jay
    Sep 30, 2021 at 19:47
  • \$\begingroup\$ @MarkoBuršič , Explain what you mean by this. \$\endgroup\$
    – Power_Electronics
    Oct 4, 2021 at 4:14
  • \$\begingroup\$ Is that you were doing wrong calculation, this circuit won't work as is. \$\endgroup\$
    – Marko Buršič
    Oct 4, 2021 at 6:26

1 Answer 1

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As Gino says in the comments, you need a push-pull drive. You’ve chosen a 74AHCT17 which is open collector/drain. It will only pull the signal low. Your circuit wont work as there’s no means to charge the capacitor. Adding a pullup resistor will help but may cause the relay to glitch on power up. Or chose a different device for U63.

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  • \$\begingroup\$ 74AHCT17APWJ is non inverting buffer , this buffer is driven at 20Khz , 80% Duty . 5V is output of this buffer. The PWM is passed through the capacitor and output of capacitor is bipolar waveform (i.e between +/- 2.5V). For +ve 2.5V it will trigger NUD3124 as NUD3124 has 2V threshold. now relay will turn ON. For PWM OFF duration the cap voltage is -2.5V , which will be clamped to ground by NUD diodes and on driver side, the 100ohm will take the potential difference. \$\endgroup\$
    – Power_Electronics
    Oct 4, 2021 at 4:13
  • \$\begingroup\$ Ah, the ahct17 is a weird ass part. The 7417 is an open collector buffer. Ok, what measurements have you done? \$\endgroup\$
    – Kartman
    Oct 4, 2021 at 5:41
  • \$\begingroup\$ Lol.. what!...Open collector buffer... you cracked me up buddy. Why you keep referring this part as open collector. there is the part , take a look at datasheet.. for the last time open collector has nothing to with it. \$\endgroup\$
    – Power_Electronics
    Oct 4, 2021 at 19:00
  • \$\begingroup\$ Thats what I acknowledged. What measurements have you done? \$\endgroup\$
    – Kartman
    Oct 4, 2021 at 21:23
  • \$\begingroup\$ Yes this circuit is tested and in use. I have done measurements at Vds of mosfet , Relay operation was tested. My question is about long term reliability of this circuit \$\endgroup\$
    – Power_Electronics
    Oct 5, 2021 at 19:51

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