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Is the diode that discharges the capacitor when it cut the current or the discharges of the capacitor that block the diode?

schematic

simulate this circuit – Schematic created using CircuitLab

The diode is blocked when Ve - Vc < Vth Ve is the source: Vc the capasitor, Vth the threshold of the diode: So the diode state neends on Vc, however Vc becomes greater than Ve because his voltage decreases less quickly, but his unload depends on the state of the diode. Thank you

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  • \$\begingroup\$ The diode does not discharge the capacitor in your circuit. I am unable to understand your language sufficiently to answer in more detail. Get google to translate your question from your natural tongue. \$\endgroup\$
    – Andy aka
    Oct 10, 2021 at 18:26
  • \$\begingroup\$ No, I mean when the diode bloc the current, is it in that moment that the capasitor wants to unload ? \$\endgroup\$
    – kodi
    Oct 10, 2021 at 18:28
  • \$\begingroup\$ Is this homework? \$\endgroup\$
    – winny
    Oct 10, 2021 at 18:33
  • \$\begingroup\$ no, this is just a wondering \$\endgroup\$
    – kodi
    Oct 10, 2021 at 18:36
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    \$\begingroup\$ If you're "just wondering" is might be very educational to simulate this circuit, for example in Falstad: falstad.com/circuit or LTSpice. \$\endgroup\$ Oct 10, 2021 at 18:41

1 Answer 1

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When the power supply has completed its positive half-cycle, the capacitor is charged to its maximum voltage. While the power supply is in its negative half-cycle, the diode blocks current from flowing from the power supply. It is during this half-cycle that the capacitor discharges through the resistor. The time constant for discharge is RC = 68 usec, so in the discharge phase, the capacitor discharges essentially to zero volts.

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