# Determining an Output Capacitor Value for LED Driver

I'm designing a buck LED circuit using a LED2000PUR (Data sheet). The issue that I am having is that the LED I'm designing for doesn't have a data sheet, and I need to determine the dynamic resistance so that I can select an appropriate output capacitor. The only parameters that I know, is the LED runs off of 3.6 V and has an If of 1.39 A.

Here is the link for what I am designing for.

Information about dynamic resistance can be found on page 15 and information about inductor and output capacitor selection can be found on page 22 of the datasheet.

My system will run off of 5 V from a powerbank.

Below is an equivalent circuit:

simulate this circuit – Schematic created using CircuitLab

The manufacturer has a tool on their website where entering the input voltages and LED specifications will output recommended components. I've preferred this as I'm not an Electrical Engineer and I find the data sheet to be oddly written.

My observations from manipulating the values are:

• Cout capacity and voltage decrease when Rd increases
• Cout values decrease when LED ripple percentage increases
• Cout values decrease and L values increase when Il Ripple percentage increases

• Unless that's a UV LED , it's an odd looking LED Vf, If, but typically at 5W it has an Rd ~ 1/2Pd or 100 mOhms. Show LED P/N & link in Q. Commented Oct 12, 2021 at 23:15
• The datasheet contains a method for determining the LED dynamic resistance at the operating point. Have you tried that method? Commented Oct 12, 2021 at 23:16
• @TonyStewartEE75 How so? White LEDs can have Vf from 3 to 5. The LED is from an AliExpress seller. It's packaged with a lens, and I've asked the seller for data sheets and information about it, but they have just provided me wattage and other optical characteristics like lux etc. Commented Oct 12, 2021 at 23:44
• Save yourself some trouble, no datasheet, no sale. Commented Oct 12, 2021 at 23:47
• @Justme the data sheet says “If the LED data sheet does not report the equivalent resistor value, it can be simply derived as the tangent to the diode I-V characteristic in the present working point” I don't have a I-V characteristic graph. But if I'm understanding correctly, the Rd value can be determined from I/V, so 1.4/3.6 = 0.39 ohms Commented Oct 12, 2021 at 23:48