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In the below circuit when I solved in methods A and B the current in the 2 ohms resistor is 3.4 A.

However, in method C the current in the 2 ohms resistor is 0.9 A.

Where is my mistake?

enter image description here

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    \$\begingroup\$ What is 2.5 A + 0.9 A? And do you see why I'm asking? \$\endgroup\$
    – jonk
    Oct 13 at 5:37
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Where is my mistake?

The mistake you have made is assuming the same current will flow through the 2 Ω resistor when you have converted the 5 volt source to a current source in parallel with it.

Consider a 5 volt source and 2 Ω resistor on their own with nothing else connected...

Does current flow through the 2 Ω series resistor when there is no load? If you then convert to a current source and parallel resistor then of course 2.5 amps will flow through the 2 Ω parallel resistor.

enter image description here

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V=1.8 is correct since Req=1.2 ohms but from (C) I2+I3 = 4A-2.5A=1.5A

1.5x1.2 = 1.8 V

Now it should be clear what I2 is and you found your mistake.

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