0
\$\begingroup\$

I'm trying to make a square wave generator with an adjustable range of output signal amplitude (between 0 and 5V) using an LM741 op-amp and the following circuit:

50% duty cycle square wave genertor, credit to https://www.electronics-tutorials.ws/opamp/op-amp-multivibrator.html

The thing is, VOUT is limited by the saturation voltage which in this chase is +-15V but from what I understand it can be varied with a voltage divider formed by R1,R2 in regular inverting amplifier circuits. In my case, R1 and R2 (alongside τ=RC) only help adjust the output frequency with the formula for the period T=2RC*ln(1+β/1-β,), my output amplitude still being stuck between ≈+-VCC.

Edit with exactly what I need: I want that my peak-to-peak amplitude to be adjustable, not stuck between ≈+-VCC. For example, with a potentiometer, voltage divider or anything to make amplitude in the range of 0-5V. I can't find a way to make it adjustable.

\$\endgroup\$
5
  • \$\begingroup\$ Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. \$\endgroup\$
    – Community Bot
    Oct 13, 2021 at 16:39
  • 1
    \$\begingroup\$ Instead of trying to convert the -14V to +14V output to 0V to 5V on that circuit that uses an antique 53 years old 741 opamp, it is much easier to use a modern rail-to-rail opamp powered from 0V and +5V, then add a "volume control" to its output. Tell your teacher about modern opamps. \$\endgroup\$
    – Audioguru
    Oct 13, 2021 at 16:50
  • 1
    \$\begingroup\$ Hey I'm 69 yrs old and I still use my old designs (lol) \$\endgroup\$ Oct 13, 2021 at 17:02
  • \$\begingroup\$ Here's my SIM with a 741 and an ideal comparator / OA tinyurl.com/yzk28r7w \$\endgroup\$ Oct 13, 2021 at 17:14
  • \$\begingroup\$ Thank you for the SIM, but that was my problem, the output amplitude is still +-VCC \$\endgroup\$
    – PowerTb321
    Oct 13, 2021 at 17:23

2 Answers 2

0
\$\begingroup\$

Your circuit generates a square wave at the output of the opamp. This is part of the oscillator signal path.

You can use that +/- 15 V signal to generate a 0..5 V signal -- e.g. use it to drive a 4.7 V zener diode via a 10k resistor. This will give about +4.7 V and -0.6 V out.

If you want an adjustable output, you could just put another R divider from Vout to GND. This may not give precisely 0 and 5 V levels. If you want that, you will need another gain stage -- even a CMOS inverter (e.g. CD4007) would work. Just drive the +/- 15 V signal into it and power it from +5 V and 0 V.

\$\endgroup\$
1
\$\begingroup\$

You have a non-rail-to-rail Op Amp with hysteresis which means the output will it NOT be 50% duty cycle NOR rail-to-rail.

The negative feedback RC integrator will slew towards the ratio of those two voltage levels.

This means there is no mechanism to offset voltage, gain without affecting frequency and/or duty cycle.

CMOS LOGIC Schmitt Triggers with 1/3 Vdd hysteresis will work much better for you. Then add any gain and offset outside the loop. And use nonlinear feedback to change duty cycle with diodes and a pot to change f.

But in future define specs for what you wish to do, then find a way to do it.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.