How to solve a parallel RLC circuit when the resistor and the inductor are in series

I have a parallel RLC circuit where the inductor is in series with the resistor. The value for the frequency is 200hz and the value for the current of the circuit is 5mA. The experimental answer is 1.241v but when I do the equations I’m given in my lectures and online(1/Z=SQRT((1/R)^2+(1/Xl - 1/Xc)^2) then times that by 5x10-3 I get a completely wrong answer. I just cannot figure out And as it’s for coursework I cannot just ignore it.any help would be greatly appreciated. this is the equation that comes up in my notes from my lectures but it does not provide the correct results )

• Can you draw the equivalent circuit that you get and you're trying to analyze with the voltage and amp. meter in the circuit? After that I can try to help you solve it. Nov 27 '21 at 20:59
• It's good that you're saying it's for coursework (adding the homework would have helped), but it would also help to show what you did, because then people would be able to point out the mistake (as opposed to someone doing the homework for you). Nov 28 '21 at 7:49
• @aconcernedcitizen as I have experiment data I have done the entire thing in excel. it is a two part coursework where you have to use the experimental date to create a graph to find the resonant frequency. then using you original values(for frequency and voltage/current) create theoretical answers and see how they compare. for the series RLC circuit this worked completely fine and I have two sets of near-identical answers(using the equation Root(R^2+(XL-Xc)^2). but for the parallel circuit as show above I simply cannot figure out the equation needed to find the correct total impedance. Nov 28 '21 at 12:55