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I am a bit confused by the diagram - are there two inductors in parallel on the primary side of the flyback transformer?

How does no current flow through v1 when the switch is closed?

enter image description here

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    \$\begingroup\$ .What was drawn like that cannot work. The current for the coupled inductance must also be switched on the primary side \$\endgroup\$
    – arnisz
    Commented Dec 18, 2021 at 7:37
  • \$\begingroup\$ The leakage inductor is outside to simulate what was lost or not coupled to secondary \$\endgroup\$
    – D.A.S.
    Commented Dec 18, 2021 at 9:13
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    \$\begingroup\$ It's most important on this question that you do provide a link to the original place where the diagram came from. \$\endgroup\$
    – Andy aka
    Commented Dec 18, 2021 at 9:45

1 Answer 1

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There is an endless debate about the flyback converter regarding the primary-to-secondary transfer mechanism: transformer or coupled inductors? When you look at the magnetic structure, it certainly looks like a transformer but in the simplified view, there is no current simultaneously circulating in the primary and the secondary.

Look at the below picture, excerpted from my seminar The Dark Side of the Flyback Converter:

enter image description here

When the main switch closes, the input voltage is applied across the primary side and a current circulates: the primary-side inductance magnetizes and stores energy. The current "enters" the transformer by the dot and would like to "leave" by the opposite dot. However, the reverse-biased diode forbids this to happen and the secondary is decoupled from the primary side during this moment: there is no current circulation in the secondary.

When the PWM controller instructs the switch to open - because the peak current has reached the setpoint for instance - then the magnetic field inside the core collapses and the voltage across the magnetizing inductance reverses in an attempt to keep the amperes-turns. The secondary diode now conducts with a current and the energy stored in the primary feeds the output capacitor and the load. The secondary current at this moment is the primary peak current at the switch opening scaled by the transformer turns ratio:

enter image description here

The output voltage \$V_{out}\$ now appears across the secondary winding (because the diode conducts) but it also flies back to the primary side scaled by the turns ratio. The voltage on the blocked transistor during this time is thus the input source plus the reflected voltage. In reality, the switching mechanisms are more complicated (there are parasitics such as the leakage inductance, the various capacitances etc.) and, during the transitions, a current certainly circulates in the primary and the secondary at the same time during a short moment. You can find details about all these effects in my book on power supplies.

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  • \$\begingroup\$ -- Just a question about slide 44, EMI radiation. In my younger years, I saw an "article" on how to assemble "transistor and radiator" so as not to emit interference to "the outside" but to "short-circuit" it to the ground. I think by inserting a special additional "shield". but impossible to find this article ... Do you something as this ? \$\endgroup\$
    – Antonio51
    Commented Dec 18, 2021 at 9:51
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    \$\begingroup\$ Perhaps figure 2 of this document will answer your question? \$\endgroup\$ Commented Dec 18, 2021 at 11:06
  • \$\begingroup\$ Very fine ! Thanks. Fig 9 & 10 ... \$\endgroup\$
    – Antonio51
    Commented Dec 18, 2021 at 11:29
  • \$\begingroup\$ Thanks for the great answer, I always learn something new from your posts. One quick question, though. If the diode wasn't there, would the coupled inductor behave as a "transformer" in the sense that it will transfer power to the secondary right away? \$\endgroup\$
    – Big6
    Commented May 26, 2022 at 14:25
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    \$\begingroup\$ @Big6, hello, oui, if the diode wasn't there to block, then you would have currents simultaneously circulating in the primary and secondary sides. Thanks for the kind words, I always try to bring some modest scientific substance rather than just quickly answering without details. \$\endgroup\$ Commented May 26, 2022 at 14:39

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