3
\$\begingroup\$

Can someone please explain to me what is the DC small-signal transfer function? I found this analysis type in LTSpice and I have no idea what it does!

My guess: It linearizes the circuit around the operating point and then basically computes the small signal transfer function, neglecting AC voltage/current sources and plugs in the frequency 0 Hz?

\$\endgroup\$

2 Answers 2

4
\$\begingroup\$

A transfer function is a mathematical relationship linking an injected stimulus \$U \$ with a response \$Y\$ observed on the output of the network under study. The ratio Y/U defines the transfer function of the circuit. Because U and Y are complex variables - defined by a magnitude and a phase - we can express the transfer function - let's call it \$H\$ - in the Laplace domain by \$H(s)=\frac{Y(s)}{U(s)}\$.

A transfer function can be written in a low-entropy form - see my book on the subject for details - in which a leading term precedes a polynomial form representative of the poles-zeroes found in the network. In general, the leading term dimension is that of the transfer function, e.g. a resistance for an impedance, a unitless number for a gain and so on. For instance, a filter featuring a pole and a zero could be described by the following transfer function linking its output to its input: \$H(s)=H_0\frac{1+\frac{s}{\omega_z}}{1+\frac{s}{\omega_p}}\$. In this expression, \$H_0\$ is called the quasi-static gain also often found under the designation of dc gain in which "dc" designates the gain obtain for \$s=0\$. This term refers to a dynamic gain obtained after two dc measurements, very close to each other during which the system under study remains linear, hence the term small-signal. Assume an amplifier biased at 3 V from a 1-V input. Bias it to 1.1 V and measure 3.3 V for instance. Then, the quasi-static gain would be defined as \$H_0=\frac{3.3-3}{1.1-1}=23\$ or 27.2 dB.

This is exactly what the .TF directive does in a SPICE simulator: it determines the small-signal dc transfer function after you have identified the input source (the stimulus) and the output node (the response). See the below example showing a low-pass filter:

enter image description here

If you run the .TF directive, then SPICE determines a dc output resistance \$R_0\$ made of the resistors in parallel and a dc insertion loss or a small-signal dc gain of -6 dB considering the divide-by-two configuration. During this calculation process, SPICE open-circuits all capacitors and short-circuits all inductors. Please note that it is not a bias point calculation but rather a dynamic measurement to determine a gain for \$s=0\$. Specifically to LTspice, I have found this well-documented link.

\$\endgroup\$
3
\$\begingroup\$

You are correct. Capacitors will become open circuits; inductors will be shorts; AC voltage and current sources will have a magnitude of 0 (but will retain their DC value).

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.