I don't want a solution; the solution is already given.
A 575 V, 60 Hz, 150 hp, 0.80 power factor lagging, 2-pole, 3-phase induction motor has the following equivalent circuit parameters as seen from the stator side:
Core losses = 600 W, friction/windage losses = 300 W, stray losses = 100 W The line current drawing by this induction motor is 150 A.
The rotor current of the given induction motor is 41 A by using the below formula as solved by the instructor:
However, if I try using the equivalent circuit in the figure below to find the rotor current:
Where is the mistake in the second approach?