Saving a bit state with OR Gate using transistor doesn't work

Question

I want make simple 1-bit memory using OR Gate like this picture

It's working what I expect when using OR gate component. I change first input state to 1 so that it will give an output state of 1. Then the current output state which is 1 is carrying to second input of OR gate. Hence, it will give state 1 forever because, as we know, the OR gate will give result 1 if one or both input is 1.

I know there's no other way to make it output 0 unless we disconnect second input from the output.

However, when I tried to make it, using transistors to create an OR gate, It's doesn't work. By that, I mean it doesn't save the state.

I'm just following configuration from internet like this. The difference is, I redirect the output to the second input.

So is there any other way how to reconfigure my transistor circuit to what I expect with OR gate memory?

Answer 1

Q2's base will be held at the same voltage as its emitter, but the base needs to be about 0.7 volts positive of the emitter for it to conduct.

Those simple two-transistor gates may have some use as a basic explanation of how a gate might work, but they won't work when combined in more complex logic circuits - the output of this sort of gate is not sufficient to drive another gate.

Answer 2

This is an example of Resistor- Transistor Logic or RTL which like Diode logic has slightly < 1 voltage gain and thus will not latch.

TTL on the other hand has a fan-out design of 10 for current or in other words a current gain of 10 by design and will support the original logic symbol expectation.

We expect logic to have a threshold and specified tolerances with variations in supply or temperature. This is somewhat like a comparator which ideally has very large gain. But gain and bandwidth we know are tradeoffs and so the gain is fixed for TTL to provide this tradeoff.