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I want to know whether I can use this d-link 3+1 CCTV cable for powering an led strip which runs at 12 volts 1 amp. The led strip is approximately 12 meters away from the smps power adapter. I checked the datasheet of the cable for power ratings on the 3 multi-strand copper wires but they're not given. All that is provided is that there are 14 strands per wire and they're 0.1mm diameter each I think. No cross sectional area or resistance is stated.

Datasheet for cable

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    \$\begingroup\$ Calculate the area of each strand. Multiply that by 14 to give you the total current carrying cross section for each wire. Than look that up in a wire gauge table to see what standard wire size comes close (say #26). Finally, use the current rating for that size wire and/or the resistance, current, and your voltage drop requirement to see if it meets your need. You do the work and post it here, and we'll check it for you. \$\endgroup\$
    – SteveSh
    Feb 5, 2022 at 12:34
  • \$\begingroup\$ Telecomms equipment and PoE (power over Ethernet) use 48 V to transfer reasonable amounts of power with small diameter wires. \$\endgroup\$
    – grahamj42
    Feb 5, 2022 at 22:55

1 Answer 1

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No cross sectional area or resistance is stated.

But, you can work that out... a 0.1 mm diameter wire has a CSA (cross sectional area) of 0.007854 mm² and, given that there are 14 of them, that's a net CSA of 0.11 mm².

Then, google an AWG table and see which wire has the closest net CSA. Here's one: -

enter image description here

It looks somewhere between AWG 27 and AWG 26. So, google what the current carrying capacity is of these types of wire: -

enter image description here

It looks like 26 AWG is only really recommended for a maximum current of 361 mA so, you might be out of luck.

I want to know whether I can use this d-link 3+1 CCTV cable for powering an led strip which runs at 12 volts 1 amp.

I think probably not.

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    \$\begingroup\$ That was quick. Thank you for helping me out. I guess I'll invest in a new 0.75mm² copper wire. Should have enough current rating and a lower resistance too. \$\endgroup\$
    – Kokachi
    Feb 5, 2022 at 12:48

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