So I've been studying on TIAs for the last days and understood everything except the term of "noise".
Let's take this TIA as an example: https://www.ti.com/lit/ds/symlink/opa380.pdf?ts=1645280932536&ref_url=https%253A%252F%252Fwww.ti.com%252Fproduct%252FOPA380
On page 12-13 noise specifications are mentioned and examples are made. I understand that the capacitance of the photodiode as well as all capacitances of the TIA itself and the feedback capacitance take a big role in calculating the frequency, at which gain is decreasing (\$f_{-3dB}\$) as well as the expected noise.
Basically you should cut of your bandwidth to the required bandwidth thru the feedback capacitor in order to decrease noise on large bandwidths. Is this correct?
Also revert biasing a photodiode decreases it's capacitance and also helps in reducing noise and gaining bandwidth (figure 10). Correct?
On page 12 "TRANSIMPEDANCE BANDWIDTH AND NOISE" they are writing about how noise increases with the square root of the feedback resistor in comparison to the linear increase of the signal. Gain should appear in the "transimpedance stage"
What is the transimpedance stage? Is it the frequency below \$f_{-3dB}\$?
Therefore one should also amplify one's signal as much as possible -> Aren't there any downside?
Last and perhaps most important question: What is the difference between "Integrated Output Noise" (figure 9) and " Output Noise" (figure 8)?
Figure 8 shows the output noise (resulting noise AFTER or BEFORE gain?) in nV/√Hz. Let's say I have a bandwidth of 10kHz, therefore my typical output noise in this exact bandwidth would be somewhere between 80 nV. Is this correct?
But what does figure 9 then want to express in comparison to figure 8? Is it the exact output noise for the equivalent circuit and gain that is established with \$R_f=10M\Omega\$ on figure 6 a-c?